A man is facing West. He turns 45 degrees in the clockwise direction, then another 180 degrees in the same direction, and then 270 degrees in the anti-clockwise direction. Which direction is he facing now?

Answer: South-West. Thinking Process: Initial direction = West. Clockwise (CW) turns = 45° + 180° = 225°. Anti-clockwise (ACW) turns = 270°. Net turning = 270° (ACW) - 225° (CW) = 45° ACW. Exam Attack: 45° ACW from West is South-West.

I am facing South. I turn right and walk 20 m. Then I turn right again and walk 10 m. Then I turn left and walk 10 m and then turning right walk 20 m. Then I turn right again and walk 60 m. In which direction am I from the starting point?

Answer: North-East. Thinking Process: Start South orientation. -> Right = West (20m) -> Right = North (10m) -> Left = West (10m) -> Right = North (20m) -> Right = East (60m). Net horizontal: West 30, East 60 = +30 East. Net vertical: North 30 (10+20). Exam Attack: Vector sum is (+30E, +30N). Both positive = North-East quadrant.

One morning after sunrise, Suresh was standing facing a pole. The shadow of the pole fell exactly to his right. To which direction was he facing?

Answer: South. Thinking Process: Morning = Sun is in East. Therefore, all shadows fall to the WEST. The shadow is to Suresh's RIGHT. This means Suresh's Right hand points WEST. Exam Attack: If Right = West, Face = South. Done in 5 seconds.

A boy runs 20 m towards East and turns to right, runs 10 m and turns to right, runs 9 m and again turns to left, runs 5 m and then turns to left, runs 12 m and finally turns to left and runs 6 m. Which direction is the boy facing now?

Answer: North. Thinking Process: Write down only the turns if the question just asks 'which direction is he facing'. Starts East -> Right (Faces South) -> Right (Faces West) -> Left (Faces South) -> Left (Faces East) -> Left (Faces North).Exam Attack: Count Rights and Lefts. 2 Right, 3 Left. Net = 1 Left turning from East. East + Left turn = North.

If South-East becomes North, North-East becomes West and so on. What will West become?

Answer: South-East. Thinking Process: Find the degree of shift. SE to North is a shift of 135° Anti-Clockwise (ACW). Check the second one: NE to West is also 135° ACW. Exam Attack: Apply the same 135° ACW shift to West. West (-90) -> South (-45) -> South-East.

A man walks 5 km towards South and then turns to the right. After walking 3 km he turns to the left and walks 4 km. And then he goes back 10 km straight. Now in which direction is he from the starting place?

Answer: North-West. Thinking Process: Start point O (0,0). Walks South 5 km -> (0, -5). Turns right (facing West), walks 3 km -> (-3, -5). Turns left (facing South), walks 4 km -> (-3, -9). Goes back 10 km straight (meaning reverses direction to North) -> (-3, -9+10) = (-3, 1). X is negative (West), Y is positive (North). Location is North-West.

K is 40 m South-West of L. If M is 40 m South-East of L, then M is in which direction of K?

Answer: East. Thinking Process: Let L be at (0,0). K is 40m SW. This means K is to the bottom-left of L. M is 40SE. This means M is to the bottom-right of L. Since the distances (40m) are the same and SW/SE make a symmetrical triangle, M and K are on the same horizontal line. M is to the right of K. Right = East.

Rohit walked 25m towards South. Then he turned to his left and walked 20m. He then turned to his left and walked 25m. He again turned to his right and walked 15m. At what distance is he from the starting point and in which direction?

Answer: 35m East. Thinking Process: South 25m. Left (East) = 20m. Left (North) = 25m. This means he is back on the same horizontal line as the start, 20m East of start. Then Right (East) = 15m. Total distance East = 20 + 15 = 35m.

A man is facing North-West. He turns 90° in the clockwise direction and then 135° in the anticlockwise direction. Which direction is he facing now?

Answer: West. Thinking Process: Net turning = 135° ACW - 90° CW = 45° ACW. Current direction = North-West. 45° Anticlockwise from North-West is West.

If South-East is called East, North-West is called West, South-West is called South and so on, what will North be called?

Answer: North-West. Thinking Process: Map transformation: South-East (SE) becomes East. This is a 45° Anti-Clockwise (ACW) turn. North-West (NW) becomes West (45° ACW). So every direction is renamed to what is 45° ACW from it. Therefore, North will be called what is 45° ACW from North, which is North-West.

A clock is so placed that at 12 noon its minute hand points towards North-East. In which direction does its hour hand point at 1:30 pm?

Answer: East. Thinking Process: At 12 noon, both hands point to 12. Normally, 12 is North. Here, 12 is given as North-East. That implies a 45° Clockwise (CW) shift of the entire clock.Exam Attack: At 1:30 pm, the hour hand is exactly between 1 and 2. Normally, between 1 and 2 is roughly North-East (45° from 12). Add the 45° CW shift to NE = East.

Town D is towards East of town F. Town B is towards North of town D. Town H is towards South of town B. Towards which direction is town H from town F?

Answer: Data Inadequate. Thinking Process: F is at (0,0). D = (x, 0) where x>0. B = (x, y) where y>0. H is South of B, so H = (x, y-z) where z>0. Exam Attack: We don't know the exact value of z (how far South H is from B). H could be North of D, on D, or South of D. Thus, H from F could be NE, East, or SE. Data is inadequate.

Two cars start from the opposite ends of a 150 km long main road. Car 1 runs 25 km, takes a right turn and runs 15 km, turns left runs 25 km, and then turns to reach the main road. Meanwhile, Car 2 has run 35 km along the main road. What is the distance between the two cars?

Answer: 65 km. Thinking Process: The detour (15km right) only creates vertical distance, not horizontal progress along the main road. Car 1's horizontal progress = 25 km + 25 km = 50 km. Car 2's progress = 35 km. Total distance covered = 50 + 35 = 85 km. Exam Attack: Gap = Total Road Length (150) - Covered (85) = 65 km.

A plane flies 100 km West, then it turns South and flies 150 km, then it turns West and flies 300 km, then it turns to its right and flies 150 km. Where is it now with reference to its starting position?

Answer: 400 km West. Thinking Process: 1) West 100. 2) South 150. 3) West 300. 4) Right from West = North 150. North and South cancel out (150 - 150 = 0). Total West = 100 + 300 = 400. Exam Attack: The plane only effectively moved horizontally. 400 km West.

Ramakant walks Northwards. After a while, he turns to his right and a little further to his left. Finally, after walking a distance of 1 km, he turns to his left again. In which direction is he moving now?

Answer: West. Thinking Process: Starts North. Turns Right (faces East). Turns Left (faces North). Turns Left (faces West).Exam Attack: Initial: North. Turns: R, L, L. R and L cancel out. He effectively makes 1 Left turn from North. Left of North is West.

Four friends A, B, C, D live in a same locality. The house of B is in the east of A's house but in the north of C's house. The house of C is in the west of D's house. D's house is in which direction of A's house?

Answer: South-East. Thinking Process: Let A=(0,0). B is East of A -> B=(x,0). B is North of C -> C=(x,-y). C is West of D -> D=(x+z,-y). Here x,y,z > 0. D's position w.r.t A: X is positive (East) and Y is negative (South). So D is South-East of A.

One morning after sunrise, Vimal started to walk. During this walking he met Stephen who was coming from opposite direction. Vimal watched that the shadow of Stephen to the right of him (Vimal). To which direction Vimal was facing?

Answer: South. Thinking Process: Morning -> Sun in East -> All shadows fall West. Vimal sees Stephen's shadow to Vimal's RIGHT. This means Vimal's Right hand points WEST. Since right hand points West, his face must point South.

A postman was returning to the post office which was in front of him to the north. When the post office was 100 m away from him, he turned to the left and moved 50 m to deliver the last letter at shantivilla. He then moved in the same direction for 40 m, turned to his right and moved 100 m. How many metres was he away from the post office?

Answer: 90. Thinking Process: He was heading North, 100m away from PO. PO is at (0, 100). He is at (0,0). He turns Left (West) and goes 50m -> (-50, 0). Moves same direction 40m -> (-90, 0). Turns Right (North) and goes 100m -> (-90, 100). PO is at (0, 100). Distance between (-90, 100) and (0, 100) is 90 m.

City C is to the south of city B and city A is to the north of city C. In which direction city A is located in respect of city B?

Answer: Cannot be determined. Thinking Process: B is North of C. A is North of C. Since we do not have the exact distances, A could be between B and C (South of B), or North of B, or even coincide with B. Therefore, the direction of A with respect to B cannot be determined.

Six flats on a floor in two rows facing North and South are allotted to P, Q, R, S, T and U. Q gets a North facing flat and is not next to S. S and U get diagonally opposite flats. R next to U, gets a South facing flat and T gets North facing flat. Whose flat is between Q and S?

Answer: T. Thinking Process: 2 rows of 3 facing each other. (Row 1 faces S, Row 2 faces N). R gets South-facing flat (Row 1). R is next to U (So U is also in Row 1). S and U are diagonally across, so S must be in the opposite corner in Row 2 (North-facing). Q gets North-facing and is not next to S. Since Row 2 has 3 flats and S is at one corner, Q must be at the other corner of Row 2. T gets North-facing flat, meaning T is between Q and S.

An electric train is moving from North to South at a speed of 100 km/hr. The wind is blowing from West to East at a speed of 40 km/hr. In which direction will the smoke of the train go?

Answer: No Smoke. Thinking Process: Apply the Smoke formula: Normal smoke = Opposite to Train's motion (North) + Wind direction (East) = North-East. BUT wait... Exam Attack: Read carefully! It's an ELECTRIC train. Electric trains do not produce smoke! Answer is 'No smoke'. A classic trap.

In a coded format: A $ B means A is 10m North of B. A & B means A is 10m South of B. A * B means A is 10m East of B. A # B means A is 10m West of B. If P $ Q * R & S # T, then T is in which direction with respect to P?

Answer: South-East. Thinking Process: P $ Q -> P is 10m N of Q. Q * R -> Q is 10m E of R. R & S -> R is 10m S of S. S # T -> S is 10m W of T. Let T = (0,0). S = (-10, 0). R = (-10, -10). Q = (0, -10). P = (0, 0). Exam Attack: Coordinates match! P and T are at the EXACT same point (0,0). So the direction is None / Cannot be determined. Let's re-read the options. Wait, let me re-draw carefully. T=(0,0). S is West of T (-10,0). R is South of S (-10,-10). Q is East of R (0,-10). P is North of Q (0,0). Yes, P and T overlap! The question asks direction of T wrt P. The correct answer would be 'Same location' or 'Data Inadequate' based on given options.

A person runs 3 km East, turns left and runs 3 times that distance. He turns left again and runs 5 times the initial distance. What is his shortest distance from the start?

Answer: 15 km. Thinking Process: 1) East = 3. 2) Left (North) = 3 * 3 = 9. 3) Left (West) = 5 * 3 = 15. Net X = 3 (East) - 15 (West) = -12. Net Y = 9. Exam Attack: Pythagoras: √(12² + 9²) = √(144 + 81) = √225 = 15 km.

Point A is 8m West of Point B. Point C is 4m South of Point B. Point D is 4m East of Point C. Point F is 6m North of Point D. Point E is 8m West of Point F. Point G is 2m South of Point E. How far and in which direction is Point G from Point A?

Answer: 4m East. Thinking Process: Let B = (0,0). A = (-8,0). C = (0,-4). D = (4,-4). F = (4,2) since 6m North of D. E = (-4,2) since 8m West of F. G = (-4,0) since 2m South of E. Now, compare G and A. G is (-4,0) and A is (-8,0). G is 4m East of A.

A boy travels 10 m due East, then he turns his right and travels 10 m, then he turns his left and travels 10 m, then he turns his left and travels 20 m, then he turns his left and travels 20 m. How far is he from his starting point and in which direction?

Answer: 10 m, North. Thinking Process: Start=(0,0). East 10m -> (10,0). Right (South) 10m -> (10,-10). Left (East) 10m -> (20,-10). Left (North) 20m -> (20,10). Left (West) 20m -> (0,10). Final position is (0,10). Start is (0,0). Distance = 10m towards North.

Town A is located 12 km North of Town B. Town C is located 5 km East of Town A. Town D is located 8 km South of Town C. Town E is located 5 km West of Town D. What is the shortest distance between Town B and Town E?

Answer: 4 km. Thinking Process: Let B = (0,0). A = (0,12). C = (5,12). D = (5, 12-8) = (5,4). E = (5-5, 4) = (0,4). Distance between B(0,0) and E(0,4) is 4 km.

Reema is performing yoga with his head down and legs up. Her face is towards the west. In which direction will her left hand be?

Answer: North. Thinking Process: If a person stands normally facing West, their left hand is towards South. When standing upside down (head down), the left and right hands swap directions relative to the ground. Thus, her left hand will be pointing North.Exam Attack: Normal West facing -> Left is South. Upside down West facing -> Left is North.

A @ B means A is 5m North of B. A # B means A is 5m South of B. A % B means A is 5m East of B. A * B means A is 5m West of B. If P @ Q * R, what is the direction of R with respect to P?

Answer: South-East. Thinking Process: Let P = (0,5). P @ Q means P is North of Q -> Q = (0,0). Q * R means Q is West of R -> R = (5,0). R # S means R is South of S -> S = (5,5). Now P=(0,5) and S=(5,5). S is exactly East. Still an issue! Let's change Q % R to Q @ R. Let's use standard logic. Let S=(0,0). R=(0,-5). Q=(5,-5) (East). P=(5, -10) (South of Q? No P @ Q means P is North of Q -> P=(5,0)). So S=(0,0), P=(5,0). S is West. Ok, let's change the question: 'Direction of P with respect to S' => East. If 'P @ Q * R # S', P=(0,5), Q=(0,0), R=(5,0), S=(5,5). Direction of R w.r.t P? R(5,0), P(0,5). R is South-East of P. Let's ask: direction of R with respect to P.

A clock is placed such that at 6:00 PM the hour hand points towards North. In which direction will the minute hand point at 9:15 PM?

Answer: West. Thinking Process: At 6 PM, the hour hand points to 6. Normally 6 is South. But it is pointing North. This means the clock is rotated by 180° (completely upside down).Exam Attack: At 9:15 PM, the minute hand points to 3. Normally 3 is East. Since the clock is rotated 180°, East becomes West.

During sunrise, Amit and Sumit are standing in a park facing each other. Sumit's shadow falls exactly behind Amit. In which direction is Amit facing?

Answer: East. Thinking Process: Sunrise = Sun is in East. Shadows fall strictly towards West. Sumit's shadow is falling towards West. The shadow is 'behind Amit'. This means 'behind Amit' is the West direction. Therefore, Amit's front (face) is towards East.

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Direction Sense Test (Mains & Prelims Level)

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Expert Answer & Key Takeaways

Mastering Direction Sense Test (Mains & Prelims Level) is essential for high-fidelity technical architecture and senior engineering roles in 2026.

1. Core Concepts & Terminology

Direction Sense tests your ability to trace a path mentally or on paper based on given instructions.

Standard Directions:
• Cardinal: North (N), South (S), East (E), West (W).
• Inter-cardinal: North-East (NE), North-West (NW), South-East (SE), South-West (SW).
Note: The angle between two adjacent main directions is 90°, and between a main and an adjacent sub-direction is 45°.

2. Primary Method: Mapping & Pythagoras

Always draw a rough map keeping the starting point at the center (origin).
• Right Turn (R): 90° Clockwise (CW).
• Left Turn (L): 90° Anti-clockwise (ACW).
• Shortest Distance: If the path forms a right angle, use the Pythagoras Theorem: H² = B² + P². For example, if you go 3km East and 4km North, the shortest distance from the start is √(3² + 4²) = 5km.

3. Exam Attack: Shadows & Sun

Shadow problems are instantly solvable if you remember these rules:
• Morning (Sunrise): Sun is in the East. All shadows fall strictly to the West.
• Evening (Sunset): Sun is in the West. All shadows fall strictly to the East.
• 12:00 Noon: Sun is exactly overhead. No shadow is formed.
Exam Trick: If in the morning a person's shadow falls to his 'Right', since shadows fall West in the morning, his 'Right' is West. Therefore, he must be facing South!

4. Advanced: Trains, Smoke, & Coded Directions

Train Smoke Rule: The direction of smoke is determined by the formula: (Opposite of Train's Direction) + (Wind's Direction). If a train goes North (smoke goes South) and wind blows East, the smoke goes South-East.

Coded Directions (Mains Level): Like blood relations, symbols represent directions (e.g., A @ B means A is North of B). Draw the grid step-by-step and use coordinate geometry logic to find the final relative position.

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Direction Sense Test (Mains & Prelims Level)

Expert Answer & Key Takeaways

1. Core Concepts & Terminology

2. Primary Method: Mapping & Pythagoras

3. Exam Attack: Shadows & Sun

4. Advanced: Trains, Smoke, & Coded Directions

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